IBM : C9050-042 Questions & Answers

Updated: Sep 20, 2026

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IBM C9050-042 Exam Syllabus Topics:

SectionObjectives
Data Processing- Arrays and Structures
  • 1. Based and controlled storage
  • 2. Array manipulation
  • 3. Structure definitions
- Character and String Handling
  • 1. Built-in string functions
  • 2. Pattern and conversion operations
  • 3. Substring processing
File and I/O Processing- File Operations
  • 1. Record processing
  • 2. Sequential and direct access files
  • 3. OPEN, READ, WRITE, and CLOSE statements
- Input and Output Formatting
  • 1. GET and PUT statements
  • 2. Formatting data
IBM Enterprise PL/I Features- Compiler and Runtime Features
  • 1. Optimization and diagnostics
  • 2. Debugging techniques
  • 3. Compiler options
- Integration Technologies
  • 1. Interoperability with C and Java
  • 2. JSON support
  • 3. XML support
PL/I Language Fundamentals- Data Types and Declarations
  • 1. Initialization and constants
  • 2. Scalar and aggregate data
  • 3. Attributes and storage classes
- Expressions and Operators
  • 1. Logical and relational operators
  • 2. Arithmetic expressions
  • 3. String operations
Program Structure and Control- Control Flow
  • 1. Iterative processing
  • 2. Branching and exception handling
  • 3. Conditional statements
- Procedures and Blocks
  • 1. Main and subprocedures
  • 2. Parameter passing
  • 3. Scope and declarations

IBM Developing with IBM Enterprise PL/I Sample Questions:

Question #1

What happens to STATIC variables declared in a procedure when the procedure is called recursively?

  • A. The values of STATIC variables from the previous invocation are saved and are available when the
    current invocation ends.
  • B. STATIC variables are allocated only once and can, therefore, be used for communication between
    invocations.
  • C. The values of STATIC variables from the previous invocation are lost.
  • D. STATIC variables are allocated and initialized at each new invocation.
Reveal Solution  Discussion  0

Correct Answer: B  🗳️

Question #2

Which code should NOT be split out into separate subroutines?

  • A. Code which must be available on different platforms.
  • B. Dead code in a program.
  • C. Redundant code in a program.
  • D. Redundant code in a group otprograms.
Reveal Solution  Discussion  0

Correct Answer: B  🗳️

Question #3

Prerequisite:
A sorted input dataset with record length 100 contains at least one record for each of the values '1', '2', '3'
in the first byte. The applied sort criteria is 1,100,ch,a.
Requirements:
1 .) All records with '1' in the first byte must be ignored.
2 .) All records with '2' in the first byte must be written to the output dataset.
3 .) If there is a '3' in the first byte, the read iteration must be left.
4 .) The program must not abend or loop infinitely.
If the code below does not fulfill the specifications provided above, which of the following is the most likely
reason?
DCL DDIN FILE RECORD INPUT;
DCL DDOUT FILE RECORD OUTPUT;
DCL 1 INSTRUC,
3 A CHAR(1),
3 * CHAR(99);
DCL EOF_IN BIT(1) INIT('0'B);
DCL (Z1,Z2,Z3,ZO) BIN FIXED(31) INIT(0);
ON ENDFILE(DDIN) EOF_IN = '1'B;
READ FILE(DDIN) INTO (INSTRUC);
LOOP: DO WHILE (^EOF_IN);
SELECT(INSTRUC.A);
WHEN('1') DO;
Z1 +-= Z1;
ITERATE LOOP;
END;
WHEN('3') DO;
Z3 = Z3+1;
LEAVE LOOP;
END;
WHEN('2') DO;
Z2 = Z2+1;
WRITE FILE(DDOUT) FROM(INSTRUC);
END;
OTHER DO;
ZO = ZO+1;
PUT SKIP LIST(INSTRUC.A);
END;
END;/*select*/
READ FILE(DDIN) INTO(INSTRUC);
END ;/*loop*/

  • A. The code does not fulfill the requirement because the last record with '2' in the first byte will be written twice to the output dataset.
  • B. The code fulfills the requirement.
  • C. The code does not fulfill the requirement because the program will loop infinitely.
  • D. The code does not fulfill the requirement because not all records with '2' in the first byte will be written to the output dataset.
Reveal Solution  Discussion  0

Correct Answer: C  🗳️

Question #4

The following function converts a character string to uppercase. What is the best way to improve the
performance?
SET_TO_UPPERCASE: PROC(CHARSTR) RETURNS (CHAR(120) VARYING);
DCL CHARSTR CHAR(120) VARYING;
DCL UCCHAR(26) INIT('ASCDEFGHIJKLMNOPQRSTUVWXYZ');
DCL LCCHAR(26) INlT('abcdefghijkImnopqrstuvxy'z');
DCL RCHAR(120) VARYING INIT(");
R = TRANSLATE(CHARSTR,UC,LC);
RETURN(R);
END SET_TO_UPPERCASE;

  • A. Use VALUE on the declares for UC and LC.
  • B. RETURN(TRANSLATE(CHARSTR,UC,LC)) to avoid the unnecessary assignment to R.
  • C. Declare variables UC and LC as STATIC.
  • D. Use the UPPERCASE function instead of SET_TO_UPPERCASE.
Reveal Solution  Discussion  0

Correct Answer: D  🗳️

Question #5

Which of the following is the most likely reason to use a debugger in a production environment?

  • A. Test a program
  • B. Enhance performance
  • C. Ensure data integrity
  • D. Investigate error situations
Reveal Solution  Discussion  0

Correct Answer: D  🗳️

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